How will a router that is configured with a classless routing protocol determine the subnet mask that should be assigned to routes that are learned from neighboring classless routers?
The subnet mask that is included in the routing updates will be used.
The subnet mask of the interface that receives the update will be used.
The subnet mask that is specified in the network command will be used.
The class of the network in the update will determine the subnet mask that is used.
Which two router component and operation pair are correctly described? (Choose two.)
Refer to the exhibit.
The network has three connected routers: R1, R2, and R3. The routes of all three routers are displayed. All routers are operational and pings are not blocked on this network.
Which ping will fail?
from R1 to 172.16.1.1
from R1 to 192.168.3.1
from R2 to 192.168.1.1
from R2 to 192.168.3.1
Which two statements are correct about the split horizon with poison reverse method of routing loop prevention? (Choose two.)
It is enabled by default on all Cisco IOS implementations.
It assigns a value that represents an infinite metric to the poisoned route.
It sends back the poisoned route update to the same interface from where it was received.
It instructs routers to hold all changes that might affect routes, for a specified period of time.
It limits the number of hops a packet can traverse through the network before it is discarded.
Which two statements describe the use of OSPF DR/BDR elections? (Choose two.)
Elections are always optional.
Elections are required in all WAN networks.
Elections are required in point-to-point networks.
Elections are required in broadcast multiaccess networks.
Elections are sometimes required in NBMA networks.
Refer to the exhibit.
The network administrator wants to set the router ID of Router1 to 192.168.100.1. What steps can the administrator take to accomplish this?
shut down the loop back interface
use the OSPF router-id 192.168.100.1 command
use the clear ip ospf process command
nothing, the router-id of Router1 is already 192.168.100.1
